(4y+6)+(7y-7)=360-(20y-11)

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Solution for (4y+6)+(7y-7)=360-(20y-11) equation: 



(4y+6)+(7y-7)=360-(20y-11)

We move all terms to the left:

(4y+6)+(7y-7)-(360-(20y-11))=0

We get rid of parentheses

4y+7y-(360-(20y-11))+6-7=0



We calculate terms in parentheses: -(360-(20y-11)), so:

360-(20y-11)

determiningTheFunctionDomain
-(20y-11)+360

We get rid of parentheses

-20y+11+360

We add all the numbers together, and all the variables

-20y+371

Back to the equation:

-(-20y+371)



We add all the numbers together, and all the variables

11y-(-20y+371)-1=0

We get rid of parentheses

11y+20y-371-1=0

We add all the numbers together, and all the variables

31y-372=0

We move all terms containing y to the left, all other terms to the right

31y=372

y=372/31

y=12

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