(4y-1)(7y+3)=0

Solution for (4y-1)(7y+3)=0 equation:

(4y-1)(7y+3)=0

We multiply parentheses ..

(+28y^2+12y-7y-3)=0

We get rid of parentheses

28y^2+12y-7y-3=0

We add all the numbers together, and all the variables

28y^2+5y-3=0

a = 28; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·28·(-3)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-19}{2*28}=\frac{-24}{56}
=-3/7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+19}{2*28}=\frac{14}{56}
=1/4
$