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(4y-1)/(5y+1)=5/7
We move all terms to the left:
(4y-1)/(5y+1)-(5/7)=0
Domain of the equation: (5y+1)!=0We add all the numbers together, and all the variables
We move all terms containing y to the left, all other terms to the right
5y!=-1
y!=-1/5
y!=-1/5
y∈R
(4y-1)/(5y+1)-(+5/7)=0
We get rid of parentheses
(4y-1)/(5y+1)-5/7=0
We calculate fractions
(28y-7)/(35y+7)+(-25y-5)/(35y+7)=0
We multiply all the terms by the denominator
(28y-7)+(-25y-5)=0
We get rid of parentheses
28y-25y-7-5=0
We add all the numbers together, and all the variables
3y-12=0
We move all terms containing y to the left, all other terms to the right
3y=12
y=12/3
y=4
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