(4y-1)/2=(y+3)/4

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Solution for (4y-1)/2=(y+3)/4 equation: 



(4y-1)/2=(y+3)/4

We move all terms to the left:

(4y-1)/2-((y+3)/4)=0

We calculate fractions


4y/()+(-((y+3)*2)/()=0



We calculate terms in parentheses: +(-((y+3)*2)/(), so:

-((y+3)*2)/(

We multiply all the terms by the denominator


-((y+3)*2)



We calculate terms in parentheses: -((y+3)*2), so:

(y+3)*2

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)



We get rid of parentheses

-2y-6

Back to the equation:

+(-2y-6)



We get rid of parentheses

4y/()-2y-6=0

We multiply all the terms by the denominator


4y-2y*()-6*()=0

We add all the numbers together, and all the variables

4y-2y*()=0

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