(4y-12)-(y-3)2=0

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Solution for (4y-12)-(y-3)2=0 equation:


Simplifying
(4y + -12) + -1(y + -3) * 2 = 0

Reorder the terms:
(-12 + 4y) + -1(y + -3) * 2 = 0

Remove parenthesis around (-12 + 4y)
-12 + 4y + -1(y + -3) * 2 = 0

Reorder the terms:
-12 + 4y + -1(-3 + y) * 2 = 0

Reorder the terms for easier multiplication:
-12 + 4y + -1 * 2(-3 + y) = 0

Multiply -1 * 2
-12 + 4y + -2(-3 + y) = 0
-12 + 4y + (-3 * -2 + y * -2) = 0
-12 + 4y + (6 + -2y) = 0

Reorder the terms:
-12 + 6 + 4y + -2y = 0

Combine like terms: -12 + 6 = -6
-6 + 4y + -2y = 0

Combine like terms: 4y + -2y = 2y
-6 + 2y = 0

Solving
-6 + 2y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 2y = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 2y = 0 + 6
2y = 0 + 6

Combine like terms: 0 + 6 = 6
2y = 6

Divide each side by '2'.
y = 3

Simplifying
y = 3

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