(4y-12=28)

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Solution for (4y-12=28) equation: 



(4y-12=28)

We move all terms to the left:

(4y-12-(28))=0

We add all the numbers together, and all the variables

(4y-40)=0

We get rid of parentheses

4y-40=0

We move all terms containing y to the left, all other terms to the right

4y=40

y=40/4

y=10

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