(4y-2)(1-y)=0

Solution for (4y-2)(1-y)=0 equation:

(4y-2)(1-y)=0

We add all the numbers together, and all the variables

(4y-2)(-1y+1)=0

We multiply parentheses ..

(-4y^2+4y+2y-2)=0

We get rid of parentheses

-4y^2+4y+2y-2=0

We add all the numbers together, and all the variables

-4y^2+6y-2=0

a = -4; b = 6; c = -2;
Δ = b2-4ac
Δ = 62-4·(-4)·(-2)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2}{2*-4}=\frac{-8}{-8}
=1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2}{2*-4}=\frac{-4}{-8}
=1/2
$