(4y-3)(4y+3)=

Solution for (4y-3)(4y+3)= equation:

Simplifying
(4y + -3)(4y + 3) = 0

Reorder the terms:
(-3 + 4y)(4y + 3) = 0

Reorder the terms:
(-3 + 4y)(3 + 4y) = 0

Multiply (-3 + 4y) * (3 + 4y)
(-3(3 + 4y) + 4y * (3 + 4y)) = 0
((3 * -3 + 4y * -3) + 4y * (3 + 4y)) = 0
((-9 + -12y) + 4y * (3 + 4y)) = 0
(-9 + -12y + (3 * 4y + 4y * 4y)) = 0
(-9 + -12y + (12y + 16y2)) = 0

Combine like terms: -12y + 12y = 0
(-9 + 0 + 16y2) = 0
(-9 + 16y2) = 0

Solving
-9 + 16y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 16y2 = 0 + 9

Combine like terms: -9 + 9 = 0
0 + 16y2 = 0 + 9
16y2 = 0 + 9

Combine like terms: 0 + 9 = 9
16y2 = 9

Divide each side by '16'.
y2 = 0.5625

Simplifying
y2 = 0.5625

Take the square root of each side:
y = {-0.75, 0.75}