(4y-35)=(2y+17)

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Solution for (4y-35)=(2y+17) equation: 



(4y-35)=(2y+17)

We move all terms to the left:

(4y-35)-((2y+17))=0

We get rid of parentheses

4y-((2y+17))-35=0



We calculate terms in parentheses: -((2y+17)), so:

(2y+17)

We get rid of parentheses

2y+17

Back to the equation:

-(2y+17)



We get rid of parentheses

4y-2y-17-35=0

We add all the numbers together, and all the variables

2y-52=0

We move all terms containing y to the left, all other terms to the right

2y=52

y=52/2

y=26

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