(4y-4)+(3y-30)=180

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Solution for (4y-4)+(3y-30)=180 equation:



(4y-4)+(3y-30)=180
We move all terms to the left:
(4y-4)+(3y-30)-(180)=0
We get rid of parentheses
4y+3y-4-30-180=0
We add all the numbers together, and all the variables
7y-214=0
We move all terms containing y to the left, all other terms to the right
7y=214
y=214/7
y=30+4/7

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