(4y-4)+3y=52

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Solution for (4y-4)+3y=52 equation:



(4y-4)+3y=52
We move all terms to the left:
(4y-4)+3y-(52)=0
We add all the numbers together, and all the variables
3y+(4y-4)-52=0
We get rid of parentheses
3y+4y-4-52=0
We add all the numbers together, and all the variables
7y-56=0
We move all terms containing y to the left, all other terms to the right
7y=56
y=56/7
y=8

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