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(4y-6)(1+y)=0
We add all the numbers together, and all the variables
(4y-6)(y+1)=0
We multiply parentheses ..
(+4y^2+4y-6y-6)=0
We get rid of parentheses
4y^2+4y-6y-6=0
We add all the numbers together, and all the variables
4y^2-2y-6=0
a = 4; b = -2; c = -6;
Δ = b2-4ac
Δ = -22-4·4·(-6)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*4}=\frac{-8}{8} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*4}=\frac{12}{8} =1+1/2 $
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