(4y-7)=(2y+11)

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Solution for (4y-7)=(2y+11) equation:



(4y-7)=(2y+11)
We move all terms to the left:
(4y-7)-((2y+11))=0
We get rid of parentheses
4y-((2y+11))-7=0
We calculate terms in parentheses: -((2y+11)), so:
(2y+11)
We get rid of parentheses
2y+11
Back to the equation:
-(2y+11)
We get rid of parentheses
4y-2y-11-7=0
We add all the numbers together, and all the variables
2y-18=0
We move all terms containing y to the left, all other terms to the right
2y=18
y=18/2
y=9

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