(4y-9)(1-y)=0

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Solution for (4y-9)(1-y)=0 equation:



(4y-9)(1-y)=0
We add all the numbers together, and all the variables
(4y-9)(-1y+1)=0
We multiply parentheses ..
(-4y^2+4y+9y-9)=0
We get rid of parentheses
-4y^2+4y+9y-9=0
We add all the numbers together, and all the variables
-4y^2+13y-9=0
a = -4; b = 13; c = -9;
Δ = b2-4ac
Δ = 132-4·(-4)·(-9)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-5}{2*-4}=\frac{-18}{-8} =2+1/4 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+5}{2*-4}=\frac{-8}{-8} =1 $

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