(4y-9)+(y+3)+(y+5)=180

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Solution for (4y-9)+(y+3)+(y+5)=180 equation: 



(4y-9)+(y+3)+(y+5)=180

We move all terms to the left:

(4y-9)+(y+3)+(y+5)-(180)=0

We get rid of parentheses

4y+y+y-9+3+5-180=0

We add all the numbers together, and all the variables

6y-181=0

We move all terms containing y to the left, all other terms to the right

6y=181

y=181/6

y=30+1/6

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