(4y/5)-(5/6)=(7/30)

Solution for (4y/5)-(5/6)=(7/30) equation:

(4y/5)-(5/6)=(7/30)

We move all terms to the left:

(4y/5)-(5/6)-((7/30))=0

We add all the numbers together, and all the variables

(+4y/5)-(+5/6)-((+7/30))=0

We get rid of parentheses

4y/5-5/6-((+7/30))=0

We calculate fractions


2160y^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

2160y^2/()+2=0

We multiply all the terms by the denominator


2160y^2+2*()=0

We add all the numbers together, and all the variables

2160y^2=0

a = 2160; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2160·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{4320}=0$