(4y=3)-(y-2)

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Solution for (4y=3)-(y-2) equation: 



(4y=3)-(y-2)

We move all terms to the left:

(4y-(3)-(y-2))=0



We calculate terms in parentheses: +(4y-3-(y-2)), so:

4y-3-(y-2)

determiningTheFunctionDomain
4y-(y-2)-3

We get rid of parentheses

4y-y+2-3

We add all the numbers together, and all the variables

3y-1

Back to the equation:

+(3y-1)



We get rid of parentheses

3y-1=0

We move all terms containing y to the left, all other terms to the right

3y=1

y=1/3

y=1/3

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