(4z)+9+(5z-3)+(z+1)=

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Solution for (4z)+9+(5z-3)+(z+1)= equation:


Simplifying
(4z) + 9 + (5z + -3) + (z + 1) = 0

Reorder the terms:
(4z) + 9 + (-3 + 5z) + (z + 1) = 0

Remove parenthesis around (-3 + 5z)
(4z) + 9 + -3 + 5z + (z + 1) = 0

Reorder the terms:
(4z) + 9 + -3 + 5z + (1 + z) = 0

Remove parenthesis around (1 + z)
(4z) + 9 + -3 + 5z + 1 + z = 0

Reorder the terms:
9 + -3 + 1 + (4z) + 5z + z = 0

Combine like terms: 9 + -3 = 6
6 + 1 + (4z) + 5z + z = 0

Combine like terms: 6 + 1 = 7
7 + (4z) + 5z + z = 0

Combine like terms: (4z) + 5z = 9z
7 + 9z + z = 0

Combine like terms: 9z + z = 10z
7 + 10z = 0

Solving
7 + 10z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 10z = 0 + -7

Combine like terms: 7 + -7 = 0
0 + 10z = 0 + -7
10z = 0 + -7

Combine like terms: 0 + -7 = -7
10z = -7

Divide each side by '10'.
z = -0.7

Simplifying
z = -0.7

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