(4z+1)+(8-(z+6))=9

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Solution for (4z+1)+(8-(z+6))=9 equation: 



(4z+1)+(8-(z+6))=9

We move all terms to the left:

(4z+1)+(8-(z+6))-(9)=0

We get rid of parentheses

4z+(8-(z+6))+1-9=0



We calculate terms in parentheses: +(8-(z+6)), so:

8-(z+6)

determiningTheFunctionDomain
-(z+6)+8

We get rid of parentheses

-z-6+8

We add all the numbers together, and all the variables

-1z+2

Back to the equation:

+(-1z+2)



We add all the numbers together, and all the variables

4z+(-1z+2)-8=0

We get rid of parentheses

4z-1z+2-8=0

We add all the numbers together, and all the variables

3z-6=0

We move all terms containing z to the left, all other terms to the right

3z=6

z=6/3

z=2

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