(4z+1)-(3z-5)=0

Solution for (4z+1)-(3z-5)=0 equation:

Simplifying
(4z + 1) + -1(3z + -5) = 0

Reorder the terms:
(1 + 4z) + -1(3z + -5) = 0

Remove parenthesis around (1 + 4z)
1 + 4z + -1(3z + -5) = 0

Reorder the terms:
1 + 4z + -1(-5 + 3z) = 0
1 + 4z + (-5 * -1 + 3z * -1) = 0
1 + 4z + (5 + -3z) = 0

Reorder the terms:
1 + 5 + 4z + -3z = 0

Combine like terms: 1 + 5 = 6
6 + 4z + -3z = 0

Combine like terms: 4z + -3z = 1z
6 + 1z = 0

Solving
6 + 1z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 1z = 0 + -6

Combine like terms: 6 + -6 = 0
0 + 1z = 0 + -6
1z = 0 + -6

Combine like terms: 0 + -6 = -6
1z = -6

Divide each side by '1'.
z = -6

Simplifying
z = -6