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(4z+1)/(3)=11
We move all terms to the left:
(4z+1)/(3)-(11)=0
We multiply all the terms by the denominator
(4z+1)-11*3=0
We add all the numbers together, and all the variables
(4z+1)-33=0
We get rid of parentheses
4z+1-33=0
We add all the numbers together, and all the variables
4z-32=0
We move all terms containing z to the left, all other terms to the right
4z=32
z=32/4
z=8
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