(4z+1)/4=(7z-1)/7

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Solution for (4z+1)/4=(7z-1)/7 equation: 



(4z+1)/4=(7z-1)/7

We move all terms to the left:

(4z+1)/4-((7z-1)/7)=0

We calculate fractions


4z/()+(-((7z-1)*4)/()=0



We calculate terms in parentheses: +(-((7z-1)*4)/(), so:

-((7z-1)*4)/(

We multiply all the terms by the denominator


-((7z-1)*4)



We calculate terms in parentheses: -((7z-1)*4), so:

(7z-1)*4

We multiply parentheses

28z-4

Back to the equation:

-(28z-4)



We get rid of parentheses

-28z+4

Back to the equation:

+(-28z+4)



We get rid of parentheses

4z/()-28z+4=0

We multiply all the terms by the denominator


4z-28z*()+4*()=0

We add all the numbers together, and all the variables

4z-28z*()=0

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