(4z+2)+(69-4z+19)=90

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Solution for (4z+2)+(69-4z+19)=90 equation: 


Simplifying
(4z + 2) + (69 + -4z + 19) = 90

Reorder the terms:
(2 + 4z) + (69 + -4z + 19) = 90

Remove parenthesis around (2 + 4z)
2 + 4z + (69 + -4z + 19) = 90

Reorder the terms:
2 + 4z + (69 + 19 + -4z) = 90

Combine like terms: 69 + 19 = 88
2 + 4z + (88 + -4z) = 90

Remove parenthesis around (88 + -4z)
2 + 4z + 88 + -4z = 90

Reorder the terms:
2 + 88 + 4z + -4z = 90

Combine like terms: 2 + 88 = 90
90 + 4z + -4z = 90

Combine like terms: 4z + -4z = 0
90 + 0 = 90
90 = 90

Add '-90' to each side of the equation.
90 + -90 = 90 + -90

Combine like terms: 90 + -90 = 0
0 = 90 + -90

Combine like terms: 90 + -90 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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