(4z+2)+(z-5)=

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Solution for (4z+2)+(z-5)= equation:


Simplifying
(4z + 2) + (z + -5) = 0

Reorder the terms:
(2 + 4z) + (z + -5) = 0

Remove parenthesis around (2 + 4z)
2 + 4z + (z + -5) = 0

Reorder the terms:
2 + 4z + (-5 + z) = 0

Remove parenthesis around (-5 + z)
2 + 4z + -5 + z = 0

Reorder the terms:
2 + -5 + 4z + z = 0

Combine like terms: 2 + -5 = -3
-3 + 4z + z = 0

Combine like terms: 4z + z = 5z
-3 + 5z = 0

Solving
-3 + 5z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 5z = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 5z = 0 + 3
5z = 0 + 3

Combine like terms: 0 + 3 = 3
5z = 3

Divide each side by '5'.
z = 0.6

Simplifying
z = 0.6

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