(4z+3)+(4z+3)+(5z)+(5z)=222

Solution for (4z+3)+(4z+3)+(5z)+(5z)=222 equation:

Simplifying
(4z + 3) + (4z + 3) + (5z) + (5z) = 222

Reorder the terms:
(3 + 4z) + (4z + 3) + (5z) + (5z) = 222

Remove parenthesis around (3 + 4z)
3 + 4z + (4z + 3) + (5z) + (5z) = 222

Reorder the terms:
3 + 4z + (3 + 4z) + (5z) + (5z) = 222

Remove parenthesis around (3 + 4z)
3 + 4z + 3 + 4z + (5z) + (5z) = 222

Reorder the terms:
3 + 3 + 4z + 4z + (5z) + (5z) = 222

Combine like terms: 3 + 3 = 6
6 + 4z + 4z + (5z) + (5z) = 222

Combine like terms: 4z + 4z = 8z
6 + 8z + (5z) + (5z) = 222

Combine like terms: 8z + (5z) = 13z
6 + 13z + (5z) = 222

Combine like terms: 13z + (5z) = 18z
6 + 18z = 222

Solving
6 + 18z = 222

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 18z = 222 + -6

Combine like terms: 6 + -6 = 0
0 + 18z = 222 + -6
18z = 222 + -6

Combine like terms: 222 + -6 = 216
18z = 216

Divide each side by '18'.
z = 12

Simplifying
z = 12