(4z+3)-4=8(2z+1)

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Solution for (4z+3)-4=8(2z+1) equation:



(4z+3)-4=8(2z+1)
We move all terms to the left:
(4z+3)-4-(8(2z+1))=0
We get rid of parentheses
4z-(8(2z+1))+3-4=0
We calculate terms in parentheses: -(8(2z+1)), so:
8(2z+1)
We multiply parentheses
16z+8
Back to the equation:
-(16z+8)
We add all the numbers together, and all the variables
4z-(16z+8)-1=0
We get rid of parentheses
4z-16z-8-1=0
We add all the numbers together, and all the variables
-12z-9=0
We move all terms containing z to the left, all other terms to the right
-12z=9
z=9/-12
z=-3/4

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