(4z+6)(1-z)=0

Solution for (4z+6)(1-z)=0 equation:

(4z+6)(1-z)=0

We add all the numbers together, and all the variables

(4z+6)(-1z+1)=0

We multiply parentheses ..

(-4z^2+4z-6z+6)=0

We get rid of parentheses

-4z^2+4z-6z+6=0

We add all the numbers together, and all the variables

-4z^2-2z+6=0

a = -4; b = -2; c = +6;
Δ = b2-4ac
Δ = -22-4·(-4)·6
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*-4}=\frac{-8}{-8}
=1
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*-4}=\frac{12}{-8}
=-1+1/2
$