(4z+7)/(z-19)=83/(z-19)

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Solution for (4z+7)/(z-19)=83/(z-19) equation: 


D( z )

z-19 = 0

z-19 = 0

z-19 = 0

z-19 = 0 // + 19

z = 19

z in (-oo:19) U (19:+oo)

(4*z+7)/(z-19) = 83/(z-19) // - 83/(z-19)

(4*z+7)/(z-19)-(83/(z-19)) = 0

(4*z+7)/(z-19)-83*(z-19)^-1 = 0

(4*z+7)/(z-19)-83/(z-19) = 0

4*z-83+7 = 0

4*z-76 = 0

(4*z-76)/(z-19) = 0

(4*z-76)/(z-19) = 0 // * z-19

4*z-76 = 0

4*z-76 = 0 // + 76

4*z = 76 // : 4

z = 76/4

z = 19

z in { 19} 

z belongs to the empty set

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