(4z-12)=16

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Solution for (4z-12)=16 equation: 



(4z-12)=16

We move all terms to the left:

(4z-12)-(16)=0

We get rid of parentheses

4z-12-16=0

We add all the numbers together, and all the variables

4z-28=0

We move all terms containing z to the left, all other terms to the right

4z=28

z=28/4

z=7

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