(4z-27)=117

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Solution for (4z-27)=117 equation: 



(4z-27)=117

We move all terms to the left:

(4z-27)-(117)=0

We get rid of parentheses

4z-27-117=0

We add all the numbers together, and all the variables

4z-144=0

We move all terms containing z to the left, all other terms to the right

4z=144

z=144/4

z=36

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