(4z/2z)=27

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Solution for (4z/2z)=27 equation: 


z in (-oo:+oo)

((4*z)/2)*z = 27 // - 27

((4*z)/2)*z-27 = 0

2*z^2 = 27 // : 2

z^2 = 27/2

z^2 = 27/2 // ^ 1/2

abs(z) = (27/2)^(1/2)

z = (27/2)^(1/2) or z = -(27/2)^(1/2)

z in { (27/2)^(1/2), -(27/2)^(1/2) }

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