(5(2k-3)-3(k+4))/3k+2

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Solution for (5(2k-3)-3(k+4))/3k+2 equation: 


k in (-oo:+oo)

k*((5*(2*k-3)-(3*(k+4)))/3)+2 = 0

k*((5*(2*k-3)-3*(k+4))/3)+2 = 0

(k*(5*(2*k-3)-3*(k+4)))/3+2 = 0

(k*(5*(2*k-3)-3*(k+4)))/3+(2*3)/3 = 0

k*(5*(2*k-3)-3*(k+4))+2*3 = 0

7*k^2-27*k+6 = 0

7*k^2-27*k+6 = 0

7*k^2-27*k+6 = 0

DELTA = (-27)^2-(4*6*7)

DELTA = 561

DELTA > 0

k = (561^(1/2)+27)/(2*7) or k = (27-561^(1/2))/(2*7)

k = (561^(1/2)+27)/14 or k = (27-561^(1/2))/14

(k-((27-561^(1/2))/14))*(k-((561^(1/2)+27)/14)) = 0

((k-((27-561^(1/2))/14))*(k-((561^(1/2)+27)/14)))/3 = 0

((k-((27-561^(1/2))/14))*(k-((561^(1/2)+27)/14)))/3 = 0 // * 3

(k-((27-561^(1/2))/14))*(k-((561^(1/2)+27)/14)) = 0

( k-((27-561^(1/2))/14) )

k-((27-561^(1/2))/14) = 0 // + (27-561^(1/2))/14

k = (27-561^(1/2))/14

( k-((561^(1/2)+27)/14) )

k-((561^(1/2)+27)/14) = 0 // + (561^(1/2)+27)/14

k = (561^(1/2)+27)/14

k in { (27-561^(1/2))/14, (561^(1/2)+27)/14 }

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