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(5(3x+2)-x+3/5+4=2(x+7)+3x-14
We move all terms to the left:
(5(3x+2)-x+3/5+4-(2(x+7)+3x-14)=0
Domain of the equation: 5+4-(2(x+7)+3x-14)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
-(2(x+7)+3x-14)!=-9
x∈R
(5(3x+2)-x+3=0
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