(5(9x-2x)+14)/6x=100

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Solution for (5(9x-2x)+14)/6x=100 equation: 



(5(9x-2x)+14)/6x=100

We move all terms to the left:

(5(9x-2x)+14)/6x-(100)=0



Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



We add all the numbers together, and all the variables

(5(+7x)+14)/6x-100=0

We multiply all the terms by the denominator


(5(+7x)+14)-100*6x=0



We calculate terms in parentheses: +(5(+7x)+14), so:

5(+7x)+14

We multiply parentheses

35x+14

Back to the equation:

+(35x+14)



Wy multiply elements

(35x+14)-600x=0

We get rid of parentheses

35x-600x+14=0

We add all the numbers together, and all the variables

-565x+14=0

We move all terms containing x to the left, all other terms to the right

-565x=-14

x=-14/-565

x=14/565

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