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(5(9x-2x)+14)/6x=100
We move all terms to the left:
(5(9x-2x)+14)/6x-(100)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
(5(+7x)+14)/6x-100=0
We multiply all the terms by the denominator
(5(+7x)+14)-100*6x=0
We calculate terms in parentheses: +(5(+7x)+14), so:Wy multiply elements
5(+7x)+14
We multiply parentheses
35x+14
Back to the equation:
+(35x+14)
(35x+14)-600x=0
We get rid of parentheses
35x-600x+14=0
We add all the numbers together, and all the variables
-565x+14=0
We move all terms containing x to the left, all other terms to the right
-565x=-14
x=-14/-565
x=14/565
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