(5(k+2)-7)/6=(13-(4-k

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Solution for (5(k+2)-7)/6=(13-(4-k equation: 



(5(k+2)-7)/6=(13-(4-k

We move all terms to the left:

(5(k+2)-7)/6-((13-(4-k)=0

We add all the numbers together, and all the variables

(5(k+2)-7)/6-((13-(-1k+4)=0

We multiply all the terms by the denominator


(5(k+2)-7)-(((13-(-1k+4))*6=0



We calculate terms in parentheses: +(5(k+2)-7), so:

5(k+2)-7

We multiply parentheses

5k+10-7

We add all the numbers together, and all the variables

5k+3

Back to the equation:

+(5k+3)



We get rid of parentheses

5k-(((13-(-1k+4))*6+3=0

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