(5)/(2y-3)=(3)/(y+5)

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Solution for (5)/(2y-3)=(3)/(y+5) equation: 


D( y )

y+5 = 0

2*y-3 = 0

y+5 = 0

y+5 = 0

y+5 = 0 // - 5

y = -5

2*y-3 = 0

2*y-3 = 0

2*y-3 = 0 // + 3

2*y = 3 // : 2

y = 3/2

y in (-oo:-5) U (-5:3/2) U (3/2:+oo)

5/(2*y-3) = 3/(y+5) // - 3/(y+5)

5/(2*y-3)-(3/(y+5)) = 0

5/(2*y-3)-3*(y+5)^-1 = 0

5/(2*y-3)-3/(y+5) = 0

(5*(y+5))/((2*y-3)*(y+5))+(-3*(2*y-3))/((2*y-3)*(y+5)) = 0

5*(y+5)-3*(2*y-3) = 0

34-y = 0

(34-y)/((2*y-3)*(y+5)) = 0

(34-y)/((2*y-3)*(y+5)) = 0 // * (2*y-3)*(y+5)

34-y = 0

34-y = 0 // - 34

-y = -34 // * -1

y = 34

y = 34

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