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(5)/(3x+1)=12
We move all terms to the left:
(5)/(3x+1)-(12)=0
Domain of the equation: (3x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
3x!=-1
x!=-1/3
x!=-1/3
x∈R
-12*(3x+1)+5=0
We multiply parentheses
-36x-12+5=0
We add all the numbers together, and all the variables
-36x-7=0
We move all terms containing x to the left, all other terms to the right
-36x=7
x=7/-36
x=-7/36
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