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(5)/x=9/8x+1
We move all terms to the left:
(5)/x-(9/8x+1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 8x+1)!=0We get rid of parentheses
x∈R
5/x-9/8x-1=0
We calculate fractions
40x/8x^2+(-9x)/8x^2-1=0
We multiply all the terms by the denominator
40x+(-9x)-1*8x^2=0
Wy multiply elements
-8x^2+40x+(-9x)=0
We get rid of parentheses
-8x^2+40x-9x=0
We add all the numbers together, and all the variables
-8x^2+31x=0
a = -8; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·(-8)·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*-8}=\frac{-62}{-16} =3+7/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*-8}=\frac{0}{-16} =0 $
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