(5*x)/10=-7/(3*x)

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Solution for (5*x)/10=-7/(3*x) equation: 


D( x )

3*x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x in (-oo:0) U (0:+oo)

(5*x)/10 = -7/(3*x) // + -7/(3*x)

(5*x)/10-(-7/(3*x)) = 0

(5*x)/10+(7/3)*x^-1 = 0

1/2*x^1+7/3*x^-1 = 0

(1/2*x^2+7/3*x^0)/(x^1) = 0 // * x^2

x^1*(1/2*x^2+7/3*x^0) = 0

x^1

(1/2)*x^2+7/3 = 0

(1/2)*x^2+7/3 = 0

DELTA = 0^2-(4*(1/2)*(7/3))

DELTA = -14/3

DELTA < 0

x in { } 

x belongs to the empty set

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