(5+1c)+8c=68

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Solution for (5+1c)+8c=68 equation: 



(5+1c)+8c=68

We move all terms to the left:

(5+1c)+8c-(68)=0

We add all the numbers together, and all the variables

(c+5)+8c-68=0

We add all the numbers together, and all the variables

8c+(c+5)-68=0

We get rid of parentheses

8c+c+5-68=0

We add all the numbers together, and all the variables

9c-63=0

We move all terms containing c to the left, all other terms to the right

9c=63

c=63/9

c=7

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