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(5+20)x2-15=x
We move all terms to the left:
(5+20)x2-15-(x)=0
We add all the numbers together, and all the variables
25x2-x-15=0
We add all the numbers together, and all the variables
25x^2-1x-15=0
a = 25; b = -1; c = -15;
Δ = b2-4ac
Δ = -12-4·25·(-15)
Δ = 1501
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{1501}}{2*25}=\frac{1-\sqrt{1501}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{1501}}{2*25}=\frac{1+\sqrt{1501}}{50} $
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