(5+2i)(2-i)=0

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Solution for (5+2i)(2-i)=0 equation:


Simplifying
(5 + 2i)(2 + -1i) = 0

Multiply (5 + 2i) * (2 + -1i)
(5(2 + -1i) + 2i * (2 + -1i)) = 0
((2 * 5 + -1i * 5) + 2i * (2 + -1i)) = 0
((10 + -5i) + 2i * (2 + -1i)) = 0
(10 + -5i + (2 * 2i + -1i * 2i)) = 0
(10 + -5i + (4i + -2i2)) = 0

Combine like terms: -5i + 4i = -1i
(10 + -1i + -2i2) = 0

Solving
10 + -1i + -2i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(2 + -1i)(5 + 2i) = 0

Subproblem 1

Set the factor '(2 + -1i)' equal to zero and attempt to solve: Simplifying 2 + -1i = 0 Solving 2 + -1i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1i = 0 + -2 -1i = 0 + -2 Combine like terms: 0 + -2 = -2 -1i = -2 Divide each side by '-1'. i = 2 Simplifying i = 2

Subproblem 2

Set the factor '(5 + 2i)' equal to zero and attempt to solve: Simplifying 5 + 2i = 0 Solving 5 + 2i = 0 Move all terms containing i to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 2i = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 2i = 0 + -5 2i = 0 + -5 Combine like terms: 0 + -5 = -5 2i = -5 Divide each side by '2'. i = -2.5 Simplifying i = -2.5

Solution

i = {2, -2.5}

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