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(5+2i)(3+4i)=7+26i
We move all terms to the left:
(5+2i)(3+4i)-(7+26i)=0
We add all the numbers together, and all the variables
(2i+5)(4i+3)-(26i+7)=0
We get rid of parentheses
(2i+5)(4i+3)-26i-7=0
We multiply parentheses ..
(+8i^2+6i+20i+15)-26i-7=0
We get rid of parentheses
8i^2+6i+20i-26i+15-7=0
We add all the numbers together, and all the variables
8i^2+8=0
a = 8; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·8·8
Δ = -256
Delta is less than zero, so there is no solution for the equation
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