(5+2i)/6i=

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Solution for (5+2i)/6i= equation: 



(5+2i)/6i=

We move all terms to the left:

(5+2i)/6i-()=0



Domain of the equation: 6i!=0

i!=0/6

i!=0

i∈R



We add all the numbers together, and all the variables

(2i+5)/6i-()=0

We add all the numbers together, and all the variables

(2i+5)/6i=0

We multiply all the terms by the denominator


(2i+5)=0

We get rid of parentheses

2i+5=0

We move all terms containing i to the left, all other terms to the right

2i=-5

i=-5/2

i=-2+1/2

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