(5+3m)(2-5m)=0

Solution for (5+3m)(2-5m)=0 equation:

(5+3m)(2-5m)=0

We add all the numbers together, and all the variables

(3m+5)(-5m+2)=0

We multiply parentheses ..

(-15m^2+6m-25m+10)=0

We get rid of parentheses

-15m^2+6m-25m+10=0

We add all the numbers together, and all the variables

-15m^2-19m+10=0

a = -15; b = -19; c = +10;
Δ = b2-4ac
Δ = -192-4·(-15)·10
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-31}{2*-15}=\frac{-12}{-30}
=2/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+31}{2*-15}=\frac{50}{-30}
=-1+2/3
$