(5+3x)3+33x=99

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Solution for (5+3x)3+33x=99 equation: 



(5+3x)3+33x=99

We move all terms to the left:

(5+3x)3+33x-(99)=0

We add all the numbers together, and all the variables

(3x+5)3+33x-99=0

We add all the numbers together, and all the variables

33x+(3x+5)3-99=0

We multiply parentheses

33x+9x+15-99=0

We add all the numbers together, and all the variables

42x-84=0

We move all terms containing x to the left, all other terms to the right

42x=84

x=84/42

x=2

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