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(5+4x)x-369=0
We add all the numbers together, and all the variables
(4x+5)x-369=0
We multiply parentheses
4x^2+5x-369=0
a = 4; b = 5; c = -369;
Δ = b2-4ac
Δ = 52-4·4·(-369)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5929}=77$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-77}{2*4}=\frac{-82}{8} =-10+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+77}{2*4}=\frac{72}{8} =9 $
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