(5+i)(4-2i)=

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Solution for (5+i)(4-2i)= equation:


Simplifying
(5 + i)(4 + -2i) = 0

Multiply (5 + i) * (4 + -2i)
(5(4 + -2i) + i(4 + -2i)) = 0
((4 * 5 + -2i * 5) + i(4 + -2i)) = 0
((20 + -10i) + i(4 + -2i)) = 0
(20 + -10i + (4 * i + -2i * i)) = 0
(20 + -10i + (4i + -2i2)) = 0

Combine like terms: -10i + 4i = -6i
(20 + -6i + -2i2) = 0

Solving
20 + -6i + -2i2 = 0

Solving for variable 'i'.

Factor out the Greatest Common Factor (GCF), '2'.
2(10 + -3i + -1i2) = 0

Factor a trinomial.
2((2 + -1i)(5 + i)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(2 + -1i)' equal to zero and attempt to solve: Simplifying 2 + -1i = 0 Solving 2 + -1i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1i = 0 + -2 -1i = 0 + -2 Combine like terms: 0 + -2 = -2 -1i = -2 Divide each side by '-1'. i = 2 Simplifying i = 2

Subproblem 2

Set the factor '(5 + i)' equal to zero and attempt to solve: Simplifying 5 + i = 0 Solving 5 + i = 0 Move all terms containing i to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + i = 0 + -5 Combine like terms: 5 + -5 = 0 0 + i = 0 + -5 i = 0 + -5 Combine like terms: 0 + -5 = -5 i = -5 Simplifying i = -5

Solution

i = {2, -5}

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