(5+n)+(n-5)=40

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Solution for (5+n)+(n-5)=40 equation: 



(5+n)+(n-5)=40

We move all terms to the left:

(5+n)+(n-5)-(40)=0

We add all the numbers together, and all the variables

(n+5)+(n-5)-40=0

We get rid of parentheses

n+n+5-5-40=0

We add all the numbers together, and all the variables

2n-40=0

We move all terms containing n to the left, all other terms to the right

2n=40

n=40/2

n=20

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