(5+u)(4u+6)=0

Solution for (5+u)(4u+6)=0 equation:

(5+u)(4u+6)=0

We add all the numbers together, and all the variables

(u+5)(4u+6)=0

We multiply parentheses ..

(+4u^2+6u+20u+30)=0

We get rid of parentheses

4u^2+6u+20u+30=0

We add all the numbers together, and all the variables

4u^2+26u+30=0

a = 4; b = 26; c = +30;
Δ = b2-4ac
Δ = 262-4·4·30
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*4}=\frac{-40}{8}
=-5
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*4}=\frac{-12}{8}
=-1+1/2
$